8 points to the person to solve this puzzle.

(In the spirit of the contest, please refrain from googling answers)

I have a cube with sides of length 3L.  I want to use my saw to cut my cube into 27 identical blocks with sides of length of L.  The trivial way to do this is with 6 cuts (2 through each face of the cube).  If I am allowed to rearrange the pieces after each cut, can I do it in fewer than 6 cuts?

Justify your answer.

~ by wcuk on August 8, 2008.

4 Responses to “8 points to the person to solve this puzzle.”

  1. Let’s see. I can think of a way to do it with 4 cuts.

    2 cuts will give you 3 boxes (I forget the correct term for the geometrical shape that has 6 rectangular faces, but I didn’t google it) of 3Lx3LxL. If you stack those so that 3LxL faces touch, 2 more cuts will give you 27 L-sided cubes.

  2. I take it back; you’d still need 2 more cuts to get 27 cubes. FAIL.

  3. The only way for the inner “center” cube of side L to exist is by cutting 6 clean faces on it. Thus, the minimum number of cuts is 6.

  4. Winner winner, chicken dinner.

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